please BANTUIN no.83 donk ka, pakai jalan ya terimakasih
[tex]\frac{\sqrt{6} }{\sqrt{3} } +\frac{\sqrt{3}}{\sqrt{6}}\\\\=\frac{\sqrt{6}.\sqrt{6}}{\sqrt{3}.\sqrt{6}} +\frac{\sqrt{3}.\sqrt{3} }{\sqrt{6}.\sqrt{3}} \\\\=\frac{\sqrt{36} }{\sqrt{18} } +\frac{\sqrt{9} }{\sqrt{18} } \\\\=\frac{6 }{\sqrt{18}}+\frac{3}{\sqrt{18} } \\\\=\frac{6+3}{\sqrt{18}}\\\\=\frac{9}{\sqrt{9.2}}\\\\=\frac{9}{\sqrt{9}.\sqrt{2}}\\\\=\frac{9}{3\sqrt{2} }\\\\=\frac{3}{\sqrt{2}}\\\\=\frac{3}{\sqrt{2} }.\frac{\sqrt{2} }{\sqrt{2} }\\\\=\frac{3\sqrt{2}}{\sqrt{4} }\\\\=\frac{3\sqrt{2}}{2}[/tex]
Jawaban : B
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